【アルファベット探し】STEP: 3 アルファベットの順番 (paizaランク D 相当) 解答例 – PHP編【Bランクレベルアップメニュー】
【Bランクレベルアップメニュー】 > 【アルファベット探し】STEP: 3 アルファベットの順番 (paizaランク D 相当)
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解答例
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<?php $input_line = trim(fgets(STDIN)); $wordcount = mb_strlen($input_line)-1; $word = str_split($input_line); $firstword = $word[0]; $lastword = $word[$wordcount]; $result = array("A" => 0, "B"=> 1, "C"=> 2, "D"=> 3, "E"=> 4, "F"=> 5, "G"=> 6, "H"=> 7, "I"=> 8, "J"=> 9, "K"=> 10, "L"=> 11, "M"=> 12, "N"=> 13, "O"=> 14, "P"=> 15, "Q"=> 16, "R"=> 17, "S"=> 18, "T"=> 19, "U"=> 20, "V"=> 21, "W"=> 22, "X"=> 23, "Y"=> 24, "Z"=> 25); $box = ["A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"]; $bigcount = $result[$lastword]; $smallcount = $result[$firstword]; $rotation = $bigcount - $smallcount; if($result[$firstword] < $result[$lastword]){ echo "true"; } else { echo "false"; } ?> |
